Chemistry 106, Chapter 16 Exercises
Concentrations of ions in solutions and Ksp
1. Using Ksp and the equilibrium concentration of one ion, calculate the equilibrium concentration of
the other ion.
-14
2+
-6
a. Cd(OH)
, Ksp = 2.5 x 10
, [Cd
] = 1.5 x 10
M
2
-9
3-
-4
b. Li
PO
, Ksp = 3.5 x 10
, [PO
] = 7.5 x 10
M
3
4
4
-4
+
c. AgNO
, Ksp = 6.0 x 10
, [Ag
] = 0.025
3
-
-4
+
-
answers: a. [OH
] = 1.3 x 10
M , b. [Li
] = 0.016 M, c. [NO
] = 0.024 M
3
+
-
2. Calculate the equilibrium concentrations of Cu
and Cl
in a saturated solution of copper (I) chloride,
-6
+
-
-3
given Ksp = 1.02 x 10
. Ans. [Cu
] = [Cl
] = 1.01 x 10
M
2+
-
3. Calculate the equilibrium concentrations of Pb
and F
in a saturated solution of lead (II) fluoride if
-8
2+
-
Ksp = 3.2 x 10
. Ans. [Pb
] = 0.0020 M, [F
] = 0.0040 M
2+
3-
4. Calculate the equilibrium concentrations of Ba
and PO
in a saturated solution of Ba
(PO
)
if Ksp
4
3
4
2
-39
2+
-8
3-
-8
= 6 x 10
. Ans. [Ba
] = 2.7 x 10
M, [PO
] = 1.8 x 10
M
4
Calculating solubilities using Ksp
-39
-10
5. Calculate the molar solubility of Fe(OH)
in water. Ksp = 3 x 10
. Ans. 1 x 10
mol/L
3
-18
-5
6. Calculate the molar solubility of Ag
PO
in water. Ksp = 1.8 x 10
. Ans. 1.6 x 10
mol/L
3
4
-10
7. Calculate the solubility in grams/liter of silver chloride (143.3 g/mol) in water. Ksp = 1.8 x 10
.
-3
Ans. 1.9 x 10
g/L
8. Calculate the solubility in grams/liter of magnesium hydroxide (58.3 g/mol) in water.
-12
-3
Ksp = 6 x 10
. Ans. 7 x 10
g/L
9. How many grams of aluminum fluoride (84 g/mol) will dissolve in 250 mL of water?
-18
-4
Ksp = 1 x 10
. Ans. 3 x 10
g
-31
-7
10. Calculate the molar solubility of Sr
(PO
)
in water. Ksp = 1 x 10
. Ans. 2.5 x 10
mol/L
3
4
2
Common Ion Effect
11. Calculate the solubility in grams/liter of silver chloride (143.3 g/mol) in the following solutions.
-10
Ksp for AgCl = 1.8 x 10
.
-7
a. 0.025 M BaCl
. Ans. 5.2 x 10
g/L
2
-7
b. 0.17 M AgNO
. Ans. 1.5 x 10
g/L
3
12. Calculate the solubility in grams/liter of magnesium hydroxide (58.3 g/mol) in the following
-12
solutions. Ksp for Mg(OH)
= 6 x 10
.
2
-8
a. 0.041 M Ba(OH)
. Ans. 5 x 10
g/L
2
-3
b. 0.0050 MgCl
. Ans. 1 x 10
g/L
2