Solution Of First Order Equations Worksheets With Answers - S. Ghorai

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S. Ghorai
1
Lecture III
Solution of first order equations
1
Separable equations
These are equations of the form
y = f (x)g(y)
Assuing g is nonzero, we divide by g and integrate to find
dy
=
f (x)dx + C
g(y)
What happens if g(y) becomes zero at a point y = y
?
0
2
Example 1. xy = y + y
Solution: We write this as
dy
dx
dy
dy
=
+ C
= ln x + C
ln y
ln(1 + y) = ln x + C
2
y + y
x
y
1 + y
Note: Strictly speaking, we should write the above solution as
ln y
ln 1 + y = ln x + C
When we wrote the solution without the modulas sign, it was (implicitly) assumed
that x > 0, y > 0. This is acceptable for problems in which the solution domain is not
given explicitly. But for some problems, the modulas sign is necessary. For example,
consider the following IVP:
2
xy = y + y
,
y( 1) =
2.
Try to solve this.
2
Reduction to separable form
2.1
Substitution method
Let the ODE be
y = F (ax + by + c)
Suppose b = 0. Substituting ax + by + c = v reduces the equation to a separable form.
If b = 0, then it is already in separable form.
2
Example 2. y = (x + y)
Solution: Let v = x + y. Then we find
2
1
v = v
+ 1
tan
v = x + C
x + y = tan(x + C)

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