Writing And Balancing Chemical Reactions, Stoichiometry, Limiting Reactants Worksheet With Answers - Chem110 Page 3
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8CHEM110 Week 5 Notes (Stoichiometry)
Page 3 of 8
Because oxygen appears in two different chemicals in the products, it is best to start in a
different place than oxygen. Start with carbon or hydrogen. Add a 3 coefficient before
carbon dioxide on the right side.
C
H
(g) + O
(g)
→
3CO
(g) + H
O(g)
3
8
2
2
2
__3__ C __3__
__8__ H __2__
__2__ O __6__
Next, balance hydrogen. Add a 4 coefficient before water on the right side.
C
H
(g) + O
(g)
→
3CO
(g) + 4H
O(g)
3
8
2
2
2
__3__ C __3__
__8__ H __8__
__2__ O _10__
The oxygen count can be fixed by adding a 5 coefficient before oxygen on the left side.
Finding the correct coefficient would have been more difficult before this step. The
reaction is now balanced.
C
H
(g) + 5O
(g)
→
3CO
(g) + 4H
O(g)
3
8
2
2
2
__3__ C __3__
__8__ H __8__
_10__ O _10__
Balance the following combustion reaction of butane C
H
.
4
10
C
H
(g) + O
(g)
→
CO
(g) + H
O(g)
4
10
2
2
2
__4__ C __1__
_10__ H __2__
__2__ O __3__
Balance carbon by adding a 4 coefficient to carbon dioxide.
C
H
(g) + O
(g)
→
4CO
(g) + H
O(g)
4
10
2
2
2
__4__ C __4__
_10__ H __2__
__2__ O __8__
Balance hydrogen by adding a 5 coefficient to water.
C
H
(g) + O
(g)
→
4CO
(g) + 5H
O(g)
4
10
2
2
2
__4__ C __4__
_10__ H _10__
__2__ O _13__
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